Q:

URGENTWhat is the area of trapezoid ABCD ?Enter your answer as a decimal or whole number in the box. Do not round at any steps. units²

Accepted Solution

A:
Answer:The answer to your question is Area = 62.5 u²Step-by-step explanation:Area = [tex]c \frac{a + b}{2}[/tex]a and b are basesc = heigth dAD = [tex]\sqrt{(x2 - x1)^{2} - (y2 - y1)^{2}  }[/tex]dAD = [tex]\sqrt{(-1 + 13)^{2} - (5 + 11)^{2}  }[/tex]dAD = [tex]\sqrt{(12)^{2} - (16)^{2}  }[/tex]dAD = [tex]\sqrt{144 + 256}[/tex]dAD = [tex]\sqrt{400}[/tex]dAD = 20 udBC = [tex]\sqrt{(3 - 0)^{2} - (2 + 2)^{2}  }[/tex]dBC = [tex]\sqrt{9 + 16}[/tex]dBC = [tex]\sqrt{25}[/tex]dBC = 5 udAB = [tex]\sqrt{(3 + 1)^{2} - (2 - 5)^{2}  }[/tex]dAB = [tex]\sqrt{(4)^{2} - (-3)^{2}  }[/tex]dAB = [tex]\sqrt{16 + 9}[/tex]dAB = [tex]\sqrt{25}[/tex]dAB = 5uArea = [tex]5 \frac{20 + 5}{2}[/tex]Area = [tex]5 \frac{25}{2}[/tex]Area = 5(12.5)Area = 62.5 u²